7x^2=25x=0

Solution for 7x^2=25x=0 equation:

7x^2=25x=0

We move all terms to the left:

7x^2-(25x)=0

a = 7; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·7·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*7}=\frac{0}{14}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*7}=\frac{50}{14}
=3+4/7
$